1.8/0.0165=108 amps
My statement has not changed, I will NOT use a primary battery that has a manufacturer maximum charge current of 6.8 Amps. There is NOTHING limiting current in the circuit to keep it at or below what the battery manufacturer has rated as a max charge current.
Yes there may be some CHEAP batteries out there that will work. My experience has been you get what you pay for most of the time. My luck with cheap stuff has been more not worth it.
ok, got it - don’t use it. Not sure where you obtained .0165…edit I see it..
But do dig a bit deeper and understand what the numbers mean.
The limiting factor for a battery is its chemistry, temperature, and state of charge.
A discharged battery will have a lower internal resistance than a fully charged one - going back to ohms law you will see that as you increase resistance in a circuit you will decrease the amps (coulombs per second) moving in a circuit.
This battery mfg is telling you that in a discharged state (~0.1vdc), the batteries internal resistance is .0147ohms (.0147=.1/6.8)…Not how much current it can deliver into a load like a motor, that’s where CCA and PCA come into play.
Said differently, it’s not the amps that charge a battery, it’s volts (potential) applied to the batteries terminals. The measured voltage at the battery terminals indicates the state of charge.
An alternator will deliver ~14.6V into a circuit up to its rated maximum current (plus a little, until it melts). This is why you can see an Odyssey PC680 battery draw 25A when discharged, and an EarthX ETX680 draw 65A when discharged. The chem differences, internal resistance, and the State of Charge all combine to limit the amount of amps flowing in the circuit, during the inaccurately named “charge cycle”.
This is typical for LA, VRLA, AGM batteries — they’re just big, chunks of lead and sulfuric acid…no smarts at all…and aircraft alternators (and automotive mostly) were also just dumb spinning things. There is no “Charging Mode” - it’s just a continuous state of current flow dictated by the difference in cell voltage and buss (alternator ) voltage.